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Here is how how I figured the ratio of power in the fundamental to power in the square wave, which contains the fundamental and lots of really odd harmonics:

The power of an AC coupled 1 volt square wave drives into 1 Ohm is  = (Vpp/2)^2

Where Vpp is the peak-to-peak voltage of the square wave.

The RMS value of the fundamental frequency component of that square wave is
= ((4/Pi) (Vpp/2*SQRT(2)))^2

That makes the ratio of the power in the fundamental component to the total power in the Square wave =8/(Pi^2), or about 81.1%.  That would mean that at best, 81.1% of a square wave driven into an antenna resonant at the fundamental frequency would be available to drive the antenna resistances (Ohmic + radiation resistance).


Back to Driver and 1 Sq. Meter Loop for 187 KHz


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Contents © 2004 Richard Cappels All Rights Reserved. http://www.projects.cappels.org/
 First posted on the World Wide Web in April, 2004. (04/04/04). Updated 6 April, 2004.

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